EQUATIONS CONTAINING VARIABLES UNDER ONE OR MORE RADICALS

Note:


Problem 2.3c:

tex2html_wrap_inline98

Answer: 0

Solution:

First make a note of the fact that you cannot take the square root of a negative number. Therefore, tex2html_wrap_inline100 .



Add 9x to both sides of the equation so that the radical term is

isolated.

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Square both sides of the equation:

tex2html_wrap_inline104

tex2html_wrap_inline106




Subtract 3x from and add 9 to both sides of the equation.

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Solve using factoring:

and or

tex2html_wrap_inline116



Check the solution x=0 by substituting 0 for x in the original equation. If after the substitution, the left side of the original equation equals the right side of the original equation, 0 is a solution.




Check the solution tex2html_wrap_inline128 by substituting -0.888889 for x in the original equation. If after the substitution, the left side of the original equation equals the right side of the original equation, -0.888889 is a solution.

Since the left side of the original equation does not equal the right side of the original equation after -0.888889 was substituted for x, then x=-0.888889 is not a solution.



You can also check the answer by graphing the equation:

displaymath74

The graph represents the right side of the original equation minus the left side of the original equation. There is one x-intercept, at the origin where x=0, therefore 0 is a solution to the equation.


If you would like to review the answer and solution to problem 2.3d, click on Solution.

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