Evaluate
Solution. First let us
complete the square
for . We get
which suggests the secant-substitution . Hence
we have
and
. Note that for x=0, we have
which gives
t=0 and for x=3, we have
which gives
.
Therefore, we have
Using the trigonometric identities (you will find them at the end of this page), we get
The technique of integration related to the powers of the
secant-function gives and
which implies
One would check easily that