Consider the series and its associated sequence of partial sums . We will say that is convergent if and only if the sequence is convergent. The total sum of the series is the limit of the sequence , which we will denote by
So as you see the convergence of a series is related to the
convergence of a sequence. Many do some serious mistakes in confusing
the convergence of the sequence of partial sums with the
convergence of the sequence of numbers .
Basic Properties.
for any .
This implies in particular that if we know sequence of partial sums
, one may generate the numbers since we have
In particular, if the sequence we are trying to add does not converge to 0, then the associated series is divergent.
converges if and only if |q|<1. Moreover we have
is convergent and moreover we have
Example. Show that the series
is divergent, even though
Answer. Note that for any , we have
Hence we have (for the associated partial sums)
Since , then we have
which implies that the series is divergent. Indeed, we do have
since
which implies
Example. Check that the following series is convergent and find its total sum
Answer. We have
Using the above properties, we see here that we are dealing with two geometric series which are convergent. Hence the original series is convergent and we have
which gives
Example. Check that the following series is convergent and find its total sum
Answer. First we need to clean the expression (by using algebraic manipulations)
We recognize a geometric series. Since , then the series is convergent and we have
Tue Dec 3 17:39:00 MST 1996