GRAPHS OF LOGARITHMIC FUNCTIONS

In this section we will illustrate, interpret, and discuss the graphs of logarithmic functions.
Vertical Shifts: A vertical shift takes place when a function is shifted up or down. The following examples look at the difference between the graph of f(x) and the graph of f(x) + C. For example, the graph of f(x) + 3 is the graph of f(x) shifted up 3 units. The graph of f(x) - 8 is the graph of f(x) shifted down 8 units.
Example 3: Graph the function
and graph the function
on the same rectangular coordinate system. Answer the following questions about each graph:
- In what quadrants is the graph of the function
located? In what quadrants is the graph of the function
located?
- What is the x-intercept and the y-intercept of the graph of the function
? What is the x-intercept and the y-intercept of the graph of the function
?
- Find the point (2, f(2)) on the graph of
and find (2, g(2)) on the graph of
. What do these two points have in common? What is the difference between the two points.
- Describe the relationship between the two graphs.
- How would you move the graph of
so that it is superimposed on the graph of
? After you move the graph, where would the point (1, 0) on
be located?
- Describe the difference between the two equations.
- You can see that the both graphs are located in quadrants I and II. Therefore, the domain (values of x) of both functions is the set of positive real numbers.
- The graph of the function f(x) has an x-intercept at x = 1. The graph of the function g(x) has an x-intercept at x = 0.049787. You can see that neither of the graphs crosses the y-axis; therefore, neither of the graphs has a y-intercept.
- The point
, rounded to (2, 0.7) for graphing purposes, is located on the graph of
.
The point
, rounded to (2, 3.7) for graphing purposes, is located on the graph of
. For each x-coordinate, the y-coordinates differ by 3.
- Both graphs have the same shape. The graph of
is nothing more than the graph of
shifted up three units.
- Shift (move) the graph of
up 3 units. Every point on the graph of
would be moved up 3 units. Therefore, the point (1, 0) would wind up at
or
after the move.
- The only difference between the two equations is the + 3. Since
,
can be rewritten
. This means that for every value of x, the function g(x) will always be 3 units larger than the function f(x).
Example 4: Graph the function
and the function
on the same rectangular coordinate system. and answer the following questions about each graph:
- In what quadrants is the graph of the function
located? In what quadrants is the graph of the function
located?
- What is the x-intercept and the y-intercept of the graph of the function
? What is the x-intercept and the y-intercept of the graph of the function
?
- Find the point (2, f(2)) on the graph of
and find (2, g(2)) on the graph of
. What do these two points have in common?
- Describe the relationship between the two graphs.
- Describe how you would shift (move) the graph of
so that it is superimposed on the graph of
. Where would the point (1, 0) on the graph of
be located after the move?
- What is the difference between the two equations?
- The graph of
is located in quadrants I and IV, and the graph of
is located in quadrants I and IV. This means that the domain (values of x) for both functions will always be positive real numbers.
- The graph of
crosses the x-axis at x = 1. Therefore, the x-intercept ix 1. The graph does not cross the y-axis; therefore, there is no y-intercept.
The graph of
crosses the x-axis at 148.413159, rounded to 148.4 for graphing purposes:
Let
and solve for x. Add 5 to both sides of the equation
and we have
.
Convert the equation
to a logarithmic equation.
.
The graph of g(x) does not cross the y-axis; therefore, the graph of g(x) has no y-intercept.
- The point
, rounded to (2, 0.7) for graphing purposes, is located on the graph of
.
The point
, rounded to (2, -4.3) for graphing purposes, is located on the graph of
. For each x-coordinate, the y-coordinates differ by 5.
- Both graphs have the same shape. The graph of
is nothing more than the graph of
shifted down 5 units.
- Shift (move) the graph of
down five units so that it is superimposed on the graph of
. When we move the graph of
down 5 units so that it is superimposed on the graph of
, every point on the graph of
is shifted down 5 units. Therefore, the point (1, 0) will be shifted down to
or
.
- The difference between the two equations is the - 5. Since
,
can be rewritten
.
If we knew that the point (c, d) is located on the graph of f(x), we can conclude that the point (c, d - 5) is located on the graph of g(x). For every value of x, the function g(x) will always be 5 units less than the function f(x).
If you would like to review another example, click on Example.

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