EQUATIONS CONTAINING VARIABLES UNDER ONE OR MORE RADICALS

Note:


Problem 2.3b:

tex2html_wrap_inline94

Answer: tex2html_wrap_inline96 (rounded)

Solution:

First make a note of the fact that you cannot take the square root of a negative number. Therefore, tex2html_wrap_inline98 .



Subtract 9x from both sides of the equation so that the radical term is

isolated.

displaymath66




Square both sides of the equation:

tex2html_wrap_inline102

tex2html_wrap_inline104




Subtract 3x and 2 from both sides of the equation.

displaymath67




Solve using the quadratic formula.

displaymath68




Simplify.

tex2html_wrap_inline108

tex2html_wrap_inline110

tex2html_wrap_inline96



Check the solution tex2html_wrap_inline110 by substituting 1.386897 for x in the original equation. If after the substitution, the left side of the original equation equals the right side of the original equation, 1.386897 is a solution.

Since the left side of the original equation does not equal the right side of the original equation after 1.386897 was substituted for x, then x=1.386897 is not a solution.

Check the solution x= 0.872362 by substituting 0.872362 in the original equation. If after the substitution, the left side of the original equation equals the right side of the original equation, 0.872362 is a solution.

Since the left side of the original equation equals the right side of the original equation after 0.872362 was substituted for x, then x=0.872362 is a solution.

You can also check the answer by graphing the equation:

displaymath69

The graph represents the right side of the original equation minus the left side of the original equation. There is only one x-intercept, at 0.872362, therefore 0.872362 is a solution to the equation.


If you would like to review the answer and solution to problem 2.3c, click on Solution.

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