EQUATIONS CONTAINING VARIABLES UNDER ONE OR MORE RADICALS

Note:



Example 1:.         $\sqrt[5]{x-10}-4=0$

Isolate the radical term

\begin{eqnarray*}\sqrt[5]{x-10} &=&4 \\
&&
\end{eqnarray*}


Raise both sides of the equation to the power 5.


\begin{eqnarray*}\left( \sqrt[5]{x-10}\right) ^{5} &=&\left( 4\right) ^{5} \\
&& \\
x &=&1,034 \\
&& \\
\end{eqnarray*}


The answer is x=1,034

Check the solution by substituting 1,034 in the original equation for x. If the left side of the equation equals the right side of the equation after the substitution, you have found the correct answer.

Left side:         $\sqrt[5]{1,034-10}-4=4-4=0$

Right Side:        0

Since the left side of the original equation equals the right side of the original equation after you substitute 1,034 for x, then 1,034 is a solution.

You can also check your solution by graphing the function

\begin{eqnarray*}f(x) &=&\sqrt[5]{x-10}-4 \\
&&
\end{eqnarray*}


The above function is formed by subtracting the right side of the original equation from the left side of the original equation. The x-intercept of the graph is the solution to the original equation. As you can see, the x-intercept is 1,034, verifying our solution.


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