Example: Solve the initial value problem
Answer: This is a separable equation. Indeed, we have
Before we get into integration we need to look for the constant
solutions. These are the roots of the equation . Since
this equation has no real roots, we conclude that no-constant solution
exists. Therefore, we proceed with the separation of the two variables
and integration. We have
,
which gives
Since
and
,
we get
The initial condition y(0)=1 gives
The particular solution to the initial value problem is
,
or in the explicit form
Last Update 6-22-98