SOLVING LOGARITHMIC EQUATIONS


Note:

If you would like an in-depth review of logarithms, the rules of logarithms, logarithmic functions and logarithmic equations, click on logarithmic function.



Solve for x in the following equation.

Problem 1:

tex2html_wrap_inline79


Answer:2



Solution:


The above equation is valid only if all of the terms are valid. The first term is valid if x>0, the second term is valid if tex2html_wrap_inline85 x > -2, and the third term is valid if tex2html_wrap_inline89 Therefore, the equation is valid when all three of these conditions are met, or when x > 0. The domain is the set of real numbers greater than 0.





Simplify both sides of the equation using the rules of logarithms.

eqnarray29





Recall that if tex2html_wrap_inline93 that a = b. Therefore, if

eqnarray33



eqnarray35





Solve for x.

eqnarray40



eqnarray43



The exact answer is tex2html_wrap_inline97





Check the answer x = 2 by substituting 2 in the original equation for x. If the left side of the equation equals the right side of the equation after the substitution, you have found the correct answer.

Since the left side of the original equation is equal to the right side of the original equation after we substitute the value 2 for x, then x = 2 is a solution.





You can also check your answer by graphing tex2html_wrap_inline113 (formed by subtracting the right side of the original equation from the left side). Look to see where the graph crosses the x-axis; that will be the real solution. Note that the graph crosses the x-axis at 2. This means that 2 is the real solution.



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